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20120414112353 is a prime number
BaseRepresentation
bin1001001001100101001100…
…01000101100101001100001
32122020111022020212012111202
410210302212020230221201
510114123102003043403
6110443105102250545
74144436422053632
oct444624610545141
978214266765452
1020120414112353
116458024256975
12230b579b86a55
13b2c468210ca9
144d7b9459d889
1524d5a138b688
hex124ca622ca61

20120414112353 has 2 divisors, whose sum is σ = 20120414112354. Its totient is φ = 20120414112352.

The previous prime is 20120414112341. The next prime is 20120414112391. The reversal of 20120414112353 is 35321141402102.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18859851040849 + 1260563071504 = 4342793^2 + 1122748^2 .

It is a cyclic number.

It is not a de Polignac number, because 20120414112353 - 238 = 19845536205409 is a prime.

It is a super-3 number, since 3×201204141123533 (a number of 41 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (20120414112553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060207056176 + 10060207056177.

It is an arithmetic number, because the mean of its divisors is an integer number (10060207056177).

Almost surely, 220120414112353 is an apocalyptic number.

It is an amenable number.

20120414112353 is a deficient number, since it is larger than the sum of its proper divisors (1).

20120414112353 is an equidigital number, since it uses as much as digits as its factorization.

20120414112353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 20120414112353 its reverse (35321141402102), we get a palindrome (55441555514455).

The spelling of 20120414112353 in words is "twenty trillion, one hundred twenty billion, four hundred fourteen million, one hundred twelve thousand, three hundred fifty-three".