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20121001132303 is a prime number
BaseRepresentation
bin1001001001100110010010…
…01000000000000100001111
32122020112211011102220111101
410210303021020000010033
510114130302242213203
6110443243232203531
74144460110462231
oct444631110000417
978215734386441
1020121001132303
1164582a5649725
12230b7026995a7
13b2c52ca13786
144d7c0c528251
1524d5d7b9341d
hex124cc920010f

20121001132303 has 2 divisors, whose sum is σ = 20121001132304. Its totient is φ = 20121001132302.

The previous prime is 20121001132217. The next prime is 20121001132327. The reversal of 20121001132303 is 30323110012102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20121001132303 is a prime.

It is a super-2 number, since 2×201210011323032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20121001132403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060500566151 + 10060500566152.

It is an arithmetic number, because the mean of its divisors is an integer number (10060500566152).

Almost surely, 220121001132303 is an apocalyptic number.

20121001132303 is a deficient number, since it is larger than the sum of its proper divisors (1).

20121001132303 is an equidigital number, since it uses as much as digits as its factorization.

20121001132303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 20121001132303 its reverse (30323110012102), we get a palindrome (50444111144405).

The spelling of 20121001132303 in words is "twenty trillion, one hundred twenty-one billion, one million, one hundred thirty-two thousand, three hundred three".