Base | Representation |
---|---|
bin | 101101101111111111100001… |
… | …001100010000000110111110 |
3 | 222101102111110120222020110012 |
4 | 231233333201030100012332 |
5 | 202333111301404013042 |
6 | 1551534352055543222 |
7 | 60244644060153614 |
oct | 5557774114200676 |
9 | 871374416866405 |
10 | 201210111001022 |
11 | 5912580213a132 |
12 | 1a697a4b08ab12 |
13 | 8837055559c16 |
14 | 379889ad276b4 |
15 | 183de0b761e82 |
hex | b6ffe13101be |
201210111001022 has 4 divisors (see below), whose sum is σ = 301815166501536. Its totient is φ = 100605055500510.
The previous prime is 201210111000971. The next prime is 201210111001037. The reversal of 201210111001022 is 220100111012102.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×2012101110010223 (a number of 44 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 201210111000988 and 201210111001006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50302527750254 + ... + 50302527750257.
It is an arithmetic number, because the mean of its divisors is an integer number (75453791625384).
Almost surely, 2201210111001022 is an apocalyptic number.
201210111001022 is a deficient number, since it is larger than the sum of its proper divisors (100605055500514).
201210111001022 is a wasteful number, since it uses less digits than its factorization.
201210111001022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100605055500513.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 201210111001022 its reverse (220100111012102), we get a palindrome (421310222013124).
The spelling of 201210111001022 in words is "two hundred one trillion, two hundred ten billion, one hundred eleven million, one thousand, twenty-two".
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