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2012102314197 = 3670700771399
BaseRepresentation
bin11101010001111010101…
…001001100100011010101
321010100120212111010000020
4131101322221030203111
5230431241143023242
64140202543335353
7265240525322643
oct35217251144325
97110525433006
102012102314197
11706367334648
12285b60bb1559
1311798196cb31
146d559d02193
153751570d6ec
hex1d47aa4c8d5

2012102314197 has 4 divisors (see below), whose sum is σ = 2682803085600. Its totient is φ = 1341401542796.

The previous prime is 2012102314111. The next prime is 2012102314247. The reversal of 2012102314197 is 7914132012102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2012102314197 - 28 = 2012102313941 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2012102314697) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335350385697 + ... + 335350385702.

It is an arithmetic number, because the mean of its divisors is an integer number (670700771400).

Almost surely, 22012102314197 is an apocalyptic number.

It is an amenable number.

2012102314197 is a deficient number, since it is larger than the sum of its proper divisors (670700771403).

2012102314197 is an equidigital number, since it uses as much as digits as its factorization.

2012102314197 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 670700771402.

The product of its (nonzero) digits is 6048, while the sum is 33.

Adding to 2012102314197 its reverse (7914132012102), we get a palindrome (9926234326299).

The spelling of 2012102314197 in words is "two trillion, twelve billion, one hundred two million, three hundred fourteen thousand, one hundred ninety-seven".

Divisors: 1 3 670700771399 2012102314197