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20121054003157 is a prime number
BaseRepresentation
bin1001001001100110011000…
…10001101011111111010101
32122020112221211221000200011
410210303030101223333111
510114130404311100112
6110443252401320221
74144461322044532
oct444631421537725
978215854830604
1020121054003157
116458322480348
12230b718336071
13b2c53a9657c3
144d7c1556bd89
1524d5dc638aa7
hex124ccc46bfd5

20121054003157 has 2 divisors, whose sum is σ = 20121054003158. Its totient is φ = 20121054003156.

The previous prime is 20121054003143. The next prime is 20121054003163. The reversal of 20121054003157 is 75130045012102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18047874461841 + 2073179541316 = 4248279^2 + 1439854^2 .

It is a cyclic number.

It is not a de Polignac number, because 20121054003157 - 211 = 20121054001109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20121054003257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060527001578 + 10060527001579.

It is an arithmetic number, because the mean of its divisors is an integer number (10060527001579).

Almost surely, 220121054003157 is an apocalyptic number.

It is an amenable number.

20121054003157 is a deficient number, since it is larger than the sum of its proper divisors (1).

20121054003157 is an equidigital number, since it uses as much as digits as its factorization.

20121054003157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8400, while the sum is 31.

Adding to 20121054003157 its reverse (75130045012102), we get a palindrome (95251099015259).

The spelling of 20121054003157 in words is "twenty trillion, one hundred twenty-one billion, fifty-four million, three thousand, one hundred fifty-seven".