Base | Representation |
---|---|
bin | 11101010001111011000… |
… | …110111001011101100011 |
3 | 21010100121102010200120021 |
4 | 131101323012321131203 |
5 | 230431300141202243 |
6 | 4140203422254311 |
7 | 265240651442011 |
oct | 35217306713543 |
9 | 7110542120507 |
10 | 2012110100323 |
11 | 706370772464 |
12 | 285b63727397 |
13 | 117983467acb |
14 | 6d55ad6b8b1 |
15 | 3751624a6ed |
hex | 1d47b1b9763 |
2012110100323 has 2 divisors, whose sum is σ = 2012110100324. Its totient is φ = 2012110100322.
The previous prime is 2012110100291. The next prime is 2012110100383. The reversal of 2012110100323 is 3230010112102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2012110100323 - 25 = 2012110100291 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2012110100297 and 2012110100306.
It is not a weakly prime, because it can be changed into another prime (2012110100383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006055050161 + 1006055050162.
It is an arithmetic number, because the mean of its divisors is an integer number (1006055050162).
Almost surely, 22012110100323 is an apocalyptic number.
2012110100323 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012110100323 is an equidigital number, since it uses as much as digits as its factorization.
2012110100323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 2012110100323 its reverse (3230010112102), we get a palindrome (5242120212425).
The spelling of 2012110100323 in words is "two trillion, twelve billion, one hundred ten million, one hundred thousand, three hundred twenty-three".
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