Base | Representation |
---|---|
bin | 11101010001111011000… |
… | …110111111010001010001 |
3 | 21010100121102011220012101 |
4 | 131101323012333101101 |
5 | 230431300142432423 |
6 | 4140203423000401 |
7 | 265240651601245 |
oct | 35217306772121 |
9 | 7110542156171 |
10 | 2012110124113 |
11 | 706370789321 |
12 | 285b63739101 |
13 | 11798347589b |
14 | 6d55ad76425 |
15 | 375162527ad |
hex | 1d47b1bf451 |
2012110124113 has 2 divisors, whose sum is σ = 2012110124114. Its totient is φ = 2012110124112.
The previous prime is 2012110123997. The next prime is 2012110124119. The reversal of 2012110124113 is 3114210112102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1561430183184 + 450679940929 = 1249572^2 + 671327^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2012110124113 is a prime.
It is not a weakly prime, because it can be changed into another prime (2012110124119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006055062056 + 1006055062057.
It is an arithmetic number, because the mean of its divisors is an integer number (1006055062057).
Almost surely, 22012110124113 is an apocalyptic number.
It is an amenable number.
2012110124113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012110124113 is an equidigital number, since it uses as much as digits as its factorization.
2012110124113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 2012110124113 its reverse (3114210112102), we get a palindrome (5126320236215).
The spelling of 2012110124113 in words is "two trillion, twelve billion, one hundred ten million, one hundred twenty-four thousand, one hundred thirteen".
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