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2012110124113 is a prime number
BaseRepresentation
bin11101010001111011000…
…110111111010001010001
321010100121102011220012101
4131101323012333101101
5230431300142432423
64140203423000401
7265240651601245
oct35217306772121
97110542156171
102012110124113
11706370789321
12285b63739101
1311798347589b
146d55ad76425
15375162527ad
hex1d47b1bf451

2012110124113 has 2 divisors, whose sum is σ = 2012110124114. Its totient is φ = 2012110124112.

The previous prime is 2012110123997. The next prime is 2012110124119. The reversal of 2012110124113 is 3114210112102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1561430183184 + 450679940929 = 1249572^2 + 671327^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2012110124113 is a prime.

It is not a weakly prime, because it can be changed into another prime (2012110124119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006055062056 + 1006055062057.

It is an arithmetic number, because the mean of its divisors is an integer number (1006055062057).

Almost surely, 22012110124113 is an apocalyptic number.

It is an amenable number.

2012110124113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012110124113 is an equidigital number, since it uses as much as digits as its factorization.

2012110124113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 2012110124113 its reverse (3114210112102), we get a palindrome (5126320236215).

The spelling of 2012110124113 in words is "two trillion, twelve billion, one hundred ten million, one hundred twenty-four thousand, one hundred thirteen".