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201211132122 = 2327111337437019
BaseRepresentation
bin1011101101100100011…
…1100011100011011010
3201020100202020120102200
42323121013203203122
511244040022211442
6232233552511030
720352125255310
oct2733107434332
9636322216380
10201211132122
1178373490740
1232bb524b476
1315c882105c0
149a4acac0b0
15537995d34c
hex2ed91e38da

201211132122 has 384 divisors, whose sum is σ = 615229655040. Its totient is φ = 45840453120.

The previous prime is 201211132117. The next prime is 201211132141. The reversal of 201211132122 is 221231112102.

201211132122 is a `hidden beast` number, since 201 + 211 + 132 + 122 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 201211132095 and 201211132104.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 28663129 + ... + 28670147.

It is an arithmetic number, because the mean of its divisors is an integer number (1602160560).

Almost surely, 2201211132122 is an apocalyptic number.

201211132122 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 201211132122, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (307614827520).

201211132122 is an abundant number, since it is smaller than the sum of its proper divisors (414018522918).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201211132122 is a wasteful number, since it uses less digits than its factorization.

201211132122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7138 (or 7135 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 201211132122 its reverse (221231112102), we get a palindrome (422442244224).

It can be divided in two parts, 201211 and 132122, that added together give a palindrome (333333).

The spelling of 201211132122 in words is "two hundred one billion, two hundred eleven million, one hundred thirty-two thousand, one hundred twenty-two".