Base | Representation |
---|---|
bin | 1001001001100110100000… |
… | …10101111000011111101111 |
3 | 2122020120010121021101101001 |
4 | 10210303100111320133233 |
5 | 10114131024241234243 |
6 | 110443303235301131 |
7 | 4144463110600603 |
oct | 444632025703757 |
9 | 78216117241331 |
10 | 20121122211823 |
11 | 6458357a28546 |
12 | 230b73714a7a7 |
13 | b2c54bb27b69 |
14 | 4d7c20645503 |
15 | 24d5e360da4d |
hex | 124cd05787ef |
20121122211823 has 2 divisors, whose sum is σ = 20121122211824. Its totient is φ = 20121122211822.
The previous prime is 20121122211809. The next prime is 20121122211877. The reversal of 20121122211823 is 32811222112102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20121122211823 - 225 = 20121088657391 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20121122211791 and 20121122211800.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20121122211023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060561105911 + 10060561105912.
It is an arithmetic number, because the mean of its divisors is an integer number (10060561105912).
Almost surely, 220121122211823 is an apocalyptic number.
20121122211823 is a deficient number, since it is larger than the sum of its proper divisors (1).
20121122211823 is an equidigital number, since it uses as much as digits as its factorization.
20121122211823 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 28.
Adding to 20121122211823 its reverse (32811222112102), we get a palindrome (52932344323925).
The spelling of 20121122211823 in words is "twenty trillion, one hundred twenty-one billion, one hundred twenty-two million, two hundred eleven thousand, eight hundred twenty-three".
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