Base | Representation |
---|---|
bin | 1001001001100110100001… |
… | …10111110100111100000011 |
3 | 2122020120011020000110120121 |
4 | 10210303100313310330003 |
5 | 10114131034031011042 |
6 | 110443304154121111 |
7 | 4144463246331334 |
oct | 444632067647403 |
9 | 78216136013517 |
10 | 20121131110147 |
11 | 6458361a55a31 |
12 | 230b73a120197 |
13 | b2c550922142 |
14 | 4d7c218c028b |
15 | 24d5e42ba367 |
hex | 124cd0df4f03 |
20121131110147 has 2 divisors, whose sum is σ = 20121131110148. Its totient is φ = 20121131110146.
The previous prime is 20121131110081. The next prime is 20121131110187. The reversal of 20121131110147 is 74101113112102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20121131110147 - 219 = 20121130585859 is a prime.
It is not a weakly prime, because it can be changed into another prime (20121131110187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060565555073 + 10060565555074.
It is an arithmetic number, because the mean of its divisors is an integer number (10060565555074).
Almost surely, 220121131110147 is an apocalyptic number.
20121131110147 is a deficient number, since it is larger than the sum of its proper divisors (1).
20121131110147 is an equidigital number, since it uses as much as digits as its factorization.
20121131110147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336, while the sum is 25.
Adding to 20121131110147 its reverse (74101113112102), we get a palindrome (94222244222249).
The spelling of 20121131110147 in words is "twenty trillion, one hundred twenty-one billion, one hundred thirty-one million, one hundred ten thousand, one hundred forty-seven".
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