Search a number
-
+
201211320000071 is a prime number
BaseRepresentation
bin101101110000000000101001…
…010000001101111001000111
3222101102121120211220202100202
4231300000221100031321013
5202333121240410000241
61551535112045001115
760245016040402313
oct5560005120157107
9871377524822322
10201211320000071
1159126272631aa7
121a698127b5319b
1388371b8b82484
14379897371ab43
15183de7c978d9b
hexb7002940de47

201211320000071 has 2 divisors, whose sum is σ = 201211320000072. Its totient is φ = 201211320000070.

The previous prime is 201211319999981. The next prime is 201211320000121. The reversal of 201211320000071 is 170000023112102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 201211320000071 - 210 = 201211319999047 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201211319999998 and 201211320000052.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201211320002071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100605660000035 + 100605660000036.

It is an arithmetic number, because the mean of its divisors is an integer number (100605660000036).

Almost surely, 2201211320000071 is an apocalyptic number.

201211320000071 is a deficient number, since it is larger than the sum of its proper divisors (1).

201211320000071 is an equidigital number, since it uses as much as digits as its factorization.

201211320000071 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 20.

Adding to 201211320000071 its reverse (170000023112102), we get a palindrome (371211343112173).

The spelling of 201211320000071 in words is "two hundred one trillion, two hundred eleven billion, three hundred twenty million, seventy-one", and thus it is an aban number.