Base | Representation |
---|---|
bin | 101101110000000000101001… |
… | …010000001101111001000111 |
3 | 222101102121120211220202100202 |
4 | 231300000221100031321013 |
5 | 202333121240410000241 |
6 | 1551535112045001115 |
7 | 60245016040402313 |
oct | 5560005120157107 |
9 | 871377524822322 |
10 | 201211320000071 |
11 | 59126272631aa7 |
12 | 1a698127b5319b |
13 | 88371b8b82484 |
14 | 379897371ab43 |
15 | 183de7c978d9b |
hex | b7002940de47 |
201211320000071 has 2 divisors, whose sum is σ = 201211320000072. Its totient is φ = 201211320000070.
The previous prime is 201211319999981. The next prime is 201211320000121. The reversal of 201211320000071 is 170000023112102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201211320000071 - 210 = 201211319999047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 201211319999998 and 201211320000052.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201211320002071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100605660000035 + 100605660000036.
It is an arithmetic number, because the mean of its divisors is an integer number (100605660000036).
Almost surely, 2201211320000071 is an apocalyptic number.
201211320000071 is a deficient number, since it is larger than the sum of its proper divisors (1).
201211320000071 is an equidigital number, since it uses as much as digits as its factorization.
201211320000071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 20.
Adding to 201211320000071 its reverse (170000023112102), we get a palindrome (371211343112173).
The spelling of 201211320000071 in words is "two hundred one trillion, two hundred eleven billion, three hundred twenty million, seventy-one", and thus it is an aban number.
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