Base | Representation |
---|---|
bin | 11101010001111011110… |
… | …000100011111100000011 |
3 | 21010100122011200120120122 |
4 | 131101323300203330003 |
5 | 230431310440202321 |
6 | 4140204452330455 |
7 | 265241143331156 |
oct | 35217360437403 |
9 | 7110564616518 |
10 | 2012121022211 |
11 | 706376952213 |
12 | 285b67313a2b |
13 | 1179857c0171 |
14 | 6d55c5b1c9d |
15 | 375171a68ab |
hex | 1d47bc23f03 |
2012121022211 has 2 divisors, whose sum is σ = 2012121022212. Its totient is φ = 2012121022210.
The previous prime is 2012121022133. The next prime is 2012121022237. The reversal of 2012121022211 is 1122201212102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2012121022211 - 210 = 2012121021187 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2012121022211.
It is not a weakly prime, because it can be changed into another prime (2012121022291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006060511105 + 1006060511106.
It is an arithmetic number, because the mean of its divisors is an integer number (1006060511106).
Almost surely, 22012121022211 is an apocalyptic number.
2012121022211 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012121022211 is an equidigital number, since it uses as much as digits as its factorization.
2012121022211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 2012121022211 its reverse (1122201212102), we get a palindrome (3134322234313).
The spelling of 2012121022211 in words is "two trillion, twelve billion, one hundred twenty-one million, twenty-two thousand, two hundred eleven".
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