Base | Representation |
---|---|
bin | 1001001001100110101011… |
… | …01001000010101010101111 |
3 | 2122020120100210120101212201 |
4 | 10210303111221002222233 |
5 | 10114131220021322203 |
6 | 110443320133042331 |
7 | 4144465240366156 |
oct | 444632551025257 |
9 | 78216323511781 |
10 | 20121211120303 |
11 | 64583a3133827 |
12 | 230b760a863a7 |
13 | b2c564387027 |
14 | 4d7c2c38a59d |
15 | 24d5eb321e1d |
hex | 124cd5a42aaf |
20121211120303 has 2 divisors, whose sum is σ = 20121211120304. Its totient is φ = 20121211120302.
The previous prime is 20121211120289. The next prime is 20121211120391. The reversal of 20121211120303 is 30302111212102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20121211120303 - 25 = 20121211120271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20121211120393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060605560151 + 10060605560152.
It is an arithmetic number, because the mean of its divisors is an integer number (10060605560152).
Almost surely, 220121211120303 is an apocalyptic number.
20121211120303 is a deficient number, since it is larger than the sum of its proper divisors (1).
20121211120303 is an equidigital number, since it uses as much as digits as its factorization.
20121211120303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 20121211120303 its reverse (30302111212102), we get a palindrome (50423322332405).
The spelling of 20121211120303 in words is "twenty trillion, one hundred twenty-one billion, two hundred eleven million, one hundred twenty thousand, three hundred three".
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