Base | Representation |
---|---|
bin | 1011101101100100110… |
… | …0011110110100001001 |
3 | 201020100211200011210000 |
4 | 2323121030132310021 |
5 | 11244040340022213 |
6 | 232234040313213 |
7 | 20352142244130 |
oct | 2733114366411 |
9 | 636324604700 |
10 | 201212423433 |
11 | 7837419293a |
12 | 32bb5772809 |
13 | 15c885732a8 |
14 | 9a4b126917 |
15 | 5379b15c73 |
hex | 2ed931ed09 |
201212423433 has 40 divisors (see below), whose sum is σ = 348643266752. Its totient is φ = 113262408864.
The previous prime is 201212423413. The next prime is 201212423443. The reversal of 201212423433 is 334324212102.
201212423433 is a `hidden beast` number, since 20 + 1 + 212 + 423 + 4 + 3 + 3 = 666.
It is not a de Polignac number, because 201212423433 - 29 = 201212422921 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 201212423397 and 201212423406.
It is not an unprimeable number, because it can be changed into a prime (201212423413) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 2610310 + ... + 2686287.
Almost surely, 2201212423433 is an apocalyptic number.
It is an amenable number.
201212423433 is a deficient number, since it is larger than the sum of its proper divisors (147430843319).
201212423433 is an equidigital number, since it uses as much as digits as its factorization.
201212423433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5296683 (or 5296674 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 201212423433 its reverse (334324212102), we get a palindrome (535536635535).
The spelling of 201212423433 in words is "two hundred one billion, two hundred twelve million, four hundred twenty-three thousand, four hundred thirty-three".
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