Base | Representation |
---|---|
bin | 11101010001111100010… |
… | …011001100001110010001 |
3 | 21010100122210202210010020 |
4 | 131101330103030032101 |
5 | 230431320301200423 |
6 | 4140205415054053 |
7 | 265241313440310 |
oct | 35217423141621 |
9 | 7110583683106 |
10 | 2012130100113 |
11 | 706380a92611 |
12 | 285b6a371329 |
13 | 11798764b0c3 |
14 | 6d55d896277 |
15 | 37517d9b4e3 |
hex | 1d47c4cc391 |
2012130100113 has 32 divisors (see below), whose sum is σ = 3112154594304. Its totient is φ = 1132522471872.
The previous prime is 2012130100109. The next prime is 2012130100129. The reversal of 2012130100113 is 3110010312102.
It is a happy number.
It is not a de Polignac number, because 2012130100113 - 22 = 2012130100109 is a prime.
It is a super-2 number, since 2×20121301001132 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2012130100092 and 2012130100101.
It is not an unprimeable number, because it can be changed into a prime (2012130102113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16580131 + ... + 16701047.
It is an arithmetic number, because the mean of its divisors is an integer number (97254831072).
Almost surely, 22012130100113 is an apocalyptic number.
It is an amenable number.
2012130100113 is a deficient number, since it is larger than the sum of its proper divisors (1100024494191).
2012130100113 is a wasteful number, since it uses less digits than its factorization.
2012130100113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 132821.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 2012130100113 its reverse (3110010312102), we get a palindrome (5122140412215).
The spelling of 2012130100113 in words is "two trillion, twelve billion, one hundred thirty million, one hundred thousand, one hundred thirteen".
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