Base | Representation |
---|---|
bin | 11101010001111100010… |
… | …100010110000101000111 |
3 | 21010100122211100011002121 |
4 | 131101330110112011013 |
5 | 230431320340341011 |
6 | 4140205425350411 |
7 | 265241316140266 |
oct | 35217424260507 |
9 | 7110584304077 |
10 | 2012130402631 |
11 | 706381179928 |
12 | 285b6a498407 |
13 | 1179877259cb |
14 | 6d55d9345dd |
15 | 37517e0ae71 |
hex | 1d47c516147 |
2012130402631 has 2 divisors, whose sum is σ = 2012130402632. Its totient is φ = 2012130402630.
The previous prime is 2012130402587. The next prime is 2012130402671. The reversal of 2012130402631 is 1362040312102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2012130402631 - 215 = 2012130369863 is a prime.
It is a super-2 number, since 2×20121304026312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2012130402596 and 2012130402605.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012130402671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006065201315 + 1006065201316.
It is an arithmetic number, because the mean of its divisors is an integer number (1006065201316).
Almost surely, 22012130402631 is an apocalyptic number.
2012130402631 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012130402631 is an equidigital number, since it uses as much as digits as its factorization.
2012130402631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 2012130402631 its reverse (1362040312102), we get a palindrome (3374170714733).
The spelling of 2012130402631 in words is "two trillion, twelve billion, one hundred thirty million, four hundred two thousand, six hundred thirty-one".
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