Base | Representation |
---|---|
bin | 101101110000000010100110… |
… | …000000110011011000001111 |
3 | 222101102210222201110211012021 |
4 | 231300002212000303120033 |
5 | 202333140032224030221 |
6 | 1551540055455351011 |
7 | 60245121644505406 |
oct | 5560024600633017 |
9 | 871383881424167 |
10 | 201213413111311 |
11 | 591271470954a7 |
12 | 1a698610b22467 |
13 | 88374606ca933 |
14 | 3798ad16d263d |
15 | 183e0515d0041 |
hex | b700a603360f |
201213413111311 has 2 divisors, whose sum is σ = 201213413111312. Its totient is φ = 201213413111310.
The previous prime is 201213413111297. The next prime is 201213413111317. The reversal of 201213413111311 is 113111314312102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201213413111311 - 25 = 201213413111279 is a prime.
It is a super-2 number, since 2×2012134131113112 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201213413111317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100606706555655 + 100606706555656.
It is an arithmetic number, because the mean of its divisors is an integer number (100606706555656).
Almost surely, 2201213413111311 is an apocalyptic number.
201213413111311 is a deficient number, since it is larger than the sum of its proper divisors (1).
201213413111311 is an equidigital number, since it uses as much as digits as its factorization.
201213413111311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
Adding to 201213413111311 its reverse (113111314312102), we get a palindrome (314324727423413).
The spelling of 201213413111311 in words is "two hundred one trillion, two hundred thirteen billion, four hundred thirteen million, one hundred eleven thousand, three hundred eleven".
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