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201213413111311 is a prime number
BaseRepresentation
bin101101110000000010100110…
…000000110011011000001111
3222101102210222201110211012021
4231300002212000303120033
5202333140032224030221
61551540055455351011
760245121644505406
oct5560024600633017
9871383881424167
10201213413111311
11591271470954a7
121a698610b22467
1388374606ca933
143798ad16d263d
15183e0515d0041
hexb700a603360f

201213413111311 has 2 divisors, whose sum is σ = 201213413111312. Its totient is φ = 201213413111310.

The previous prime is 201213413111297. The next prime is 201213413111317. The reversal of 201213413111311 is 113111314312102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 201213413111311 - 25 = 201213413111279 is a prime.

It is a super-2 number, since 2×2012134131113112 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201213413111317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100606706555655 + 100606706555656.

It is an arithmetic number, because the mean of its divisors is an integer number (100606706555656).

Almost surely, 2201213413111311 is an apocalyptic number.

201213413111311 is a deficient number, since it is larger than the sum of its proper divisors (1).

201213413111311 is an equidigital number, since it uses as much as digits as its factorization.

201213413111311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 201213413111311 its reverse (113111314312102), we get a palindrome (314324727423413).

The spelling of 201213413111311 in words is "two hundred one trillion, two hundred thirteen billion, four hundred thirteen million, one hundred eleven thousand, three hundred eleven".