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20121400113 = 331216359141
BaseRepresentation
bin10010101111010101…
…000011001100110001
31220221021222000220020
4102233111003030301
5312202034300423
613124343234053
71311425036043
oct225725031461
956837860806
1020121400113
1185960077a1
123a96748929
131b888a1c19
14d8c487a93
157cb74b4e3
hex4af543331

20121400113 has 8 divisors (see below), whose sum is σ = 27693970176. Its totient is φ = 12981548400.

The previous prime is 20121400111. The next prime is 20121400133. The reversal of 20121400113 is 31100412102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 20121400113 - 21 = 20121400111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20121400092 and 20121400101.

It is not an unprimeable number, because it can be changed into a prime (20121400111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 108179478 + ... + 108179663.

It is an arithmetic number, because the mean of its divisors is an integer number (3461746272).

Almost surely, 220121400113 is an apocalyptic number.

It is an amenable number.

20121400113 is a deficient number, since it is larger than the sum of its proper divisors (7572570063).

20121400113 is a wasteful number, since it uses less digits than its factorization.

20121400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 216359175.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 20121400113 its reverse (31100412102), we get a palindrome (51221812215).

The spelling of 20121400113 in words is "twenty billion, one hundred twenty-one million, four hundred thousand, one hundred thirteen".

Divisors: 1 3 31 93 216359141 649077423 6707133371 20121400113