Base | Representation |
---|---|
bin | 10010101111010101… |
… | …000011001100110001 |
3 | 1220221021222000220020 |
4 | 102233111003030301 |
5 | 312202034300423 |
6 | 13124343234053 |
7 | 1311425036043 |
oct | 225725031461 |
9 | 56837860806 |
10 | 20121400113 |
11 | 85960077a1 |
12 | 3a96748929 |
13 | 1b888a1c19 |
14 | d8c487a93 |
15 | 7cb74b4e3 |
hex | 4af543331 |
20121400113 has 8 divisors (see below), whose sum is σ = 27693970176. Its totient is φ = 12981548400.
The previous prime is 20121400111. The next prime is 20121400133. The reversal of 20121400113 is 31100412102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 20121400113 - 21 = 20121400111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20121400092 and 20121400101.
It is not an unprimeable number, because it can be changed into a prime (20121400111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 108179478 + ... + 108179663.
It is an arithmetic number, because the mean of its divisors is an integer number (3461746272).
Almost surely, 220121400113 is an apocalyptic number.
It is an amenable number.
20121400113 is a deficient number, since it is larger than the sum of its proper divisors (7572570063).
20121400113 is a wasteful number, since it uses less digits than its factorization.
20121400113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 216359175.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 20121400113 its reverse (31100412102), we get a palindrome (51221812215).
The spelling of 20121400113 in words is "twenty billion, one hundred twenty-one million, four hundred thousand, one hundred thirteen".
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