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2012143102357 is a prime number
BaseRepresentation
bin11101010001111101000…
…100110010100110010101
321010100200201020100211211
4131101331010302212111
5230431332113233412
64140211001501421
7265241532112603
oct35217504624625
97110621210754
102012143102357
11706388363373
12285b727a1871
1311798a25133b
146d5614bc873
15375190b8ca7
hex1d47d132995

2012143102357 has 2 divisors, whose sum is σ = 2012143102358. Its totient is φ = 2012143102356.

The previous prime is 2012143102301. The next prime is 2012143102367. The reversal of 2012143102357 is 7532013412102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1558717292196 + 453425810161 = 1248486^2 + 673369^2 .

It is a cyclic number.

It is not a de Polignac number, because 2012143102357 - 211 = 2012143100309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2012143102367) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006071551178 + 1006071551179.

It is an arithmetic number, because the mean of its divisors is an integer number (1006071551179).

Almost surely, 22012143102357 is an apocalyptic number.

It is an amenable number.

2012143102357 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012143102357 is an equidigital number, since it uses as much as digits as its factorization.

2012143102357 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 31.

Adding to 2012143102357 its reverse (7532013412102), we get a palindrome (9544156514459).

The spelling of 2012143102357 in words is "two trillion, twelve billion, one hundred forty-three million, one hundred two thousand, three hundred fifty-seven".