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201220033345 = 540244006669
BaseRepresentation
bin1011101101100110100…
…1100000101101000001
3201020101100222210121121
42323121221200231001
511244044312031340
6232234511352241
720352264030352
oct2733151405501
9636340883547
10201220033345
1178378510321
1232bb8222681
1315c8a008cb6
149a4c147d29
15537a61a94a
hex2ed9a60b41

201220033345 has 4 divisors (see below), whose sum is σ = 241464040020. Its totient is φ = 160976026672.

The previous prime is 201220033309. The next prime is 201220033351. The reversal of 201220033345 is 543330022102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 61825330609 + 139394702736 = 248647^2 + 373356^2 .

It is a cyclic number.

It is not a de Polignac number, because 201220033345 - 215 = 201220000577 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20122003330 + ... + 20122003339.

It is an arithmetic number, because the mean of its divisors is an integer number (60366010005).

Almost surely, 2201220033345 is an apocalyptic number.

It is an amenable number.

201220033345 is a deficient number, since it is larger than the sum of its proper divisors (40244006675).

201220033345 is an equidigital number, since it uses as much as digits as its factorization.

201220033345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40244006674.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 201220033345 its reverse (543330022102), we get a palindrome (744550055447).

The spelling of 201220033345 in words is "two hundred one billion, two hundred twenty million, thirty-three thousand, three hundred forty-five".

Divisors: 1 5 40244006669 201220033345