Base | Representation |
---|---|
bin | 11101010010000000101… |
… | …011010011110000100111 |
3 | 21010100211220221110202221 |
4 | 131102000223103300213 |
5 | 230431443101000203 |
6 | 4140221001013211 |
7 | 265243164544360 |
oct | 35220053236047 |
9 | 7110756843687 |
10 | 2012203531303 |
11 | 706409487549 |
12 | 285b8aa84207 |
13 | 11799991b604 |
14 | 6d56952cb67 |
15 | 3751e553abd |
hex | 1d480ad3c27 |
2012203531303 has 4 divisors (see below), whose sum is σ = 2299661178640. Its totient is φ = 1724745883968.
The previous prime is 2012203531291. The next prime is 2012203531321. The reversal of 2012203531303 is 3031353022102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2012203531303 - 221 = 2012201434151 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2012203541303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143728823658 + ... + 143728823671.
It is an arithmetic number, because the mean of its divisors is an integer number (574915294660).
Almost surely, 22012203531303 is an apocalyptic number.
2012203531303 is a deficient number, since it is larger than the sum of its proper divisors (287457647337).
2012203531303 is an equidigital number, since it uses as much as digits as its factorization.
2012203531303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 287457647336.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 2012203531303 its reverse (3031353022102), we get a palindrome (5043556553405).
The spelling of 2012203531303 in words is "two trillion, twelve billion, two hundred three million, five hundred thirty-one thousand, three hundred three".
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