Base | Representation |
---|---|
bin | 1001001001101000010111… |
… | …11000110001000011000111 |
3 | 2122020122201020001212010102 |
4 | 10210310023320301003013 |
5 | 10114140101012241403 |
6 | 110443550323314315 |
7 | 4144526631136061 |
oct | 444641370610307 |
9 | 78218636055112 |
10 | 20122121212103 |
11 | 645881a929209 |
12 | 230b97581b99b |
13 | b2c67aaa4ca1 |
14 | 4d7cb71b2731 |
15 | 24d651193b88 |
hex | 124d0be310c7 |
20122121212103 has 2 divisors, whose sum is σ = 20122121212104. Its totient is φ = 20122121212102.
The previous prime is 20122121212073. The next prime is 20122121212111. The reversal of 20122121212103 is 30121212122102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20122121212103 - 228 = 20121852776647 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20122121212183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061060606051 + 10061060606052.
It is an arithmetic number, because the mean of its divisors is an integer number (10061060606052).
Almost surely, 220122121212103 is an apocalyptic number.
20122121212103 is a deficient number, since it is larger than the sum of its proper divisors (1).
20122121212103 is an equidigital number, since it uses as much as digits as its factorization.
20122121212103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 20122121212103 its reverse (30121212122102), we get a palindrome (50243333334205).
Subtracting 20122121212103 from its reverse (30121212122102), we obtain a palindrome (9999090909999).
The spelling of 20122121212103 in words is "twenty trillion, one hundred twenty-two billion, one hundred twenty-one million, two hundred twelve thousand, one hundred three".
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