Base | Representation |
---|---|
bin | 11101010010000001101… |
… | …110101101011011110001 |
3 | 21010100220011012010211022 |
4 | 131102001232231123301 |
5 | 230432012111400423 |
6 | 4140222431425225 |
7 | 265243500664055 |
oct | 35220156553361 |
9 | 7110804163738 |
10 | 2012221200113 |
11 | 706418455373 |
12 | 285b94985215 |
13 | 1179a0496927 |
14 | 6d56ba0bc65 |
15 | 37520d93dc8 |
hex | 1d481bad6f1 |
2012221200113 has 2 divisors, whose sum is σ = 2012221200114. Its totient is φ = 2012221200112.
The previous prime is 2012221200103. The next prime is 2012221200127. The reversal of 2012221200113 is 3110021222102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1985540264464 + 26680935649 = 1409092^2 + 163343^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012221200113 - 224 = 2012204422897 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2012221200091 and 2012221200100.
It is not a weakly prime, because it can be changed into another prime (2012221200103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006110600056 + 1006110600057.
It is an arithmetic number, because the mean of its divisors is an integer number (1006110600057).
Almost surely, 22012221200113 is an apocalyptic number.
It is an amenable number.
2012221200113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012221200113 is an equidigital number, since it uses as much as digits as its factorization.
2012221200113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 2012221200113 its reverse (3110021222102), we get a palindrome (5122242422215).
The spelling of 2012221200113 in words is "two trillion, twelve billion, two hundred twenty-one million, two hundred thousand, one hundred thirteen".
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