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201223001133000 = 2332537112989112501
BaseRepresentation
bin101101110000001011100001…
…100000001100111111001000
3222101110201201221000210022200
4231300023201200030333020
5202333314201242224000
61551544323124120200
760245611360366410
oct5560134140147710
9871421657023280
10201223001133000
11591302172a3070
121a69a447b36060
13883832ac41652
143799360c53640
15183e413210500
hexb702e180cfc8

201223001133000 has 1536 divisors, whose sum is σ = 887062969728000. Its totient is φ = 39916800000000.

The previous prime is 201223001132977. The next prime is 201223001133019. The reversal of 201223001133000 is 331100322102.

201223001133000 is a `hidden beast` number, since 2 + 0 + 1 + 22 + 300 + 11 + 330 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 1788576750 + ... + 1788689250.

It is an arithmetic number, because the mean of its divisors is an integer number (577514954250).

Almost surely, 2201223001133000 is an apocalyptic number.

201223001133000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201223001133000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (443531484864000).

201223001133000 is an abundant number, since it is smaller than the sum of its proper divisors (685839968595000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201223001133000 is a wasteful number, since it uses less digits than its factorization.

201223001133000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 112664 (or 112647 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 201223001133000 its reverse (331100322102), we get a palindrome (201554101455102).

The spelling of 201223001133000 in words is "two hundred one trillion, two hundred twenty-three billion, one million, one hundred thirty-three thousand".