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20123023111020 = 22335531136222217
BaseRepresentation
bin1001001001101010000011…
…01001001111001101101100
32122020202001002011001212000
410210311001221033031230
510114143422404023040
6110444220022212300
74144561162144014
oct444650151171554
978222032131760
1020123023111020
116459142a38215
12230bb87884090
13b2c7928b4a9b
144d7d60ca4c44
1524d6a5448130
hex124d41a4f36c

20123023111020 has 192 divisors, whose sum is σ = 64350676333440. Its totient is φ = 5218298781696.

The previous prime is 20123023111001. The next prime is 20123023111069. The reversal of 20123023111020 is 2011132032102.

20123023111020 is a `hidden beast` number, since 20 + 1 + 2 + 302 + 311 + 10 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 20123023110984 and 20123023111002.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 122952 + ... + 6345168.

It is an arithmetic number, because the mean of its divisors is an integer number (335159772570).

Almost surely, 220123023111020 is an apocalyptic number.

20123023111020 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20123023111020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (32175338166720).

20123023111020 is an abundant number, since it is smaller than the sum of its proper divisors (44227653222420).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20123023111020 is a wasteful number, since it uses less digits than its factorization.

20123023111020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6222401 (or 6222393 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 20123023111020 its reverse (2011132032102), we get a palindrome (22134155143122).

The spelling of 20123023111020 in words is "twenty trillion, one hundred twenty-three billion, twenty-three million, one hundred eleven thousand, twenty".