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20123113013149 is a prime number
BaseRepresentation
bin1001001001101010001110…
…00000001011111110011101
32122020202021100022120101111
410210311013000023332131
510114144113412410044
6110444232553142021
74144563333251236
oct444650700137635
978222240276344
1020123113013149
116459189761aa3
12230bbb19ba911
13b2c7a8401303
144d7d6cbc808d
1524d6ad2a5b34
hex124d4700bf9d

20123113013149 has 2 divisors, whose sum is σ = 20123113013150. Its totient is φ = 20123113013148.

The previous prime is 20123113013099. The next prime is 20123113013173. The reversal of 20123113013149 is 94131031132102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12485572781049 + 7637540232100 = 3533493^2 + 2763610^2 .

It is a cyclic number.

It is not a de Polignac number, because 20123113013149 - 211 = 20123113011101 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20123113013149.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20123113017149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061556506574 + 10061556506575.

It is an arithmetic number, because the mean of its divisors is an integer number (10061556506575).

Almost surely, 220123113013149 is an apocalyptic number.

It is an amenable number.

20123113013149 is a deficient number, since it is larger than the sum of its proper divisors (1).

20123113013149 is an equidigital number, since it uses as much as digits as its factorization.

20123113013149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 20123113013149 in words is "twenty trillion, one hundred twenty-three billion, one hundred thirteen million, thirteen thousand, one hundred forty-nine".