Base | Representation |
---|---|
bin | 11101010010000111001… |
… | …101110000000001010101 |
3 | 21010101010120100101211202 |
4 | 131102013031300001111 |
5 | 230432204141121003 |
6 | 4140235520042245 |
7 | 265245666114104 |
oct | 35220715600125 |
9 | 7111116311752 |
10 | 2012313223253 |
11 | 706465398753 |
12 | 285bbb763385 |
13 | 1179b65766a8 |
14 | 6d579d2403b |
15 | 37528ec0088 |
hex | 1d487370055 |
2012313223253 has 2 divisors, whose sum is σ = 2012313223254. Its totient is φ = 2012313223252.
The previous prime is 2012313223229. The next prime is 2012313223369. The reversal of 2012313223253 is 3523223132102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1593913825009 + 418399398244 = 1262503^2 + 646838^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012313223253 - 222 = 2012309028949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012313223213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006156611626 + 1006156611627.
It is an arithmetic number, because the mean of its divisors is an integer number (1006156611627).
Almost surely, 22012313223253 is an apocalyptic number.
It is an amenable number.
2012313223253 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012313223253 is an equidigital number, since it uses as much as digits as its factorization.
2012313223253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 29.
Adding to 2012313223253 its reverse (3523223132102), we get a palindrome (5535536355355).
The spelling of 2012313223253 in words is "two trillion, twelve billion, three hundred thirteen million, two hundred twenty-three thousand, two hundred fifty-three".
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