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20123133214397 is a prime number
BaseRepresentation
bin1001001001101010010000…
…01101001111111010111101
32122020202022202022220021212
410210311020031033322331
510114144134100330042
6110444234554134205
74144564000046063
oct444651015177275
978222282286255
1020123133214397
11645919a0aa544
12230bbb8721365
13b2c7ac655205
144d7d71766033
1524d6aee46482
hex124d4834febd

20123133214397 has 2 divisors, whose sum is σ = 20123133214398. Its totient is φ = 20123133214396.

The previous prime is 20123133214321. The next prime is 20123133214411. The reversal of 20123133214397 is 79341233132102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10706023264036 + 9417109950361 = 3272006^2 + 3068731^2 .

It is a cyclic number.

It is not a de Polignac number, because 20123133214397 - 214 = 20123133198013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20123133211397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061566607198 + 10061566607199.

It is an arithmetic number, because the mean of its divisors is an integer number (10061566607199).

Almost surely, 220123133214397 is an apocalyptic number.

It is an amenable number.

20123133214397 is a deficient number, since it is larger than the sum of its proper divisors (1).

20123133214397 is an equidigital number, since it uses as much as digits as its factorization.

20123133214397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 163296, while the sum is 41.

Adding to 20123133214397 its reverse (79341233132102), we get a palindrome (99464366346499).

The spelling of 20123133214397 in words is "twenty trillion, one hundred twenty-three billion, one hundred thirty-three million, two hundred fourteen thousand, three hundred ninety-seven".