Base | Representation |
---|---|
bin | 1001001001101010011000… |
… | …11000100001100111101111 |
3 | 2122020202111122011120022212 |
4 | 10210311030120201213233 |
5 | 10114144310014414333 |
6 | 110444245540001035 |
7 | 4144565510433053 |
oct | 444651430414757 |
9 | 78222448146285 |
10 | 20123203279343 |
11 | 645922570535a |
12 | 231001809017b |
13 | b2c7c1017468 |
14 | 4d7d7aba3c63 |
15 | 24d6b6186448 |
hex | 124d4c6219ef |
20123203279343 has 2 divisors, whose sum is σ = 20123203279344. Its totient is φ = 20123203279342.
The previous prime is 20123203279339. The next prime is 20123203279373. The reversal of 20123203279343 is 34397230232102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20123203279343 - 22 = 20123203279339 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20123203279343.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20123203279373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061601639671 + 10061601639672.
It is an arithmetic number, because the mean of its divisors is an integer number (10061601639672).
Almost surely, 220123203279343 is an apocalyptic number.
20123203279343 is a deficient number, since it is larger than the sum of its proper divisors (1).
20123203279343 is an equidigital number, since it uses as much as digits as its factorization.
20123203279343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 326592, while the sum is 41.
The spelling of 20123203279343 in words is "twenty trillion, one hundred twenty-three billion, two hundred three million, two hundred seventy-nine thousand, three hundred forty-three".
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