Base | Representation |
---|---|
bin | 1001001001101010011000… |
… | …11000101001100111110101 |
3 | 2122020202111122020020021201 |
4 | 10210311030120221213311 |
5 | 10114144310021441432 |
6 | 110444245540412501 |
7 | 4144565510630443 |
oct | 444651430514765 |
9 | 78222448206251 |
10 | 20123203312117 |
11 | 6459225727a44 |
12 | 23100180a7131 |
13 | b2c7c1029359 |
14 | 4d7d7abb1b93 |
15 | 24d6b6190ee7 |
hex | 124d4c6299f5 |
20123203312117 has 2 divisors, whose sum is σ = 20123203312118. Its totient is φ = 20123203312116.
The previous prime is 20123203312081. The next prime is 20123203312141. The reversal of 20123203312117 is 71121330232102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16017396726276 + 4105806585841 = 4002174^2 + 2026279^2 .
It is a cyclic number.
It is not a de Polignac number, because 20123203312117 - 235 = 20088843573749 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20123203312217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061601656058 + 10061601656059.
It is an arithmetic number, because the mean of its divisors is an integer number (10061601656059).
Almost surely, 220123203312117 is an apocalyptic number.
It is an amenable number.
20123203312117 is a deficient number, since it is larger than the sum of its proper divisors (1).
20123203312117 is an equidigital number, since it uses as much as digits as its factorization.
20123203312117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 20123203312117 its reverse (71121330232102), we get a palindrome (91244533544219).
The spelling of 20123203312117 in words is "twenty trillion, one hundred twenty-three billion, two hundred three million, three hundred twelve thousand, one hundred seventeen".
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