Base | Representation |
---|---|
bin | 11101010010000111110… |
… | …110110111110100011111 |
3 | 21010101011022122002000110 |
4 | 131102013312313310133 |
5 | 230432214421044403 |
6 | 4140240543101103 |
7 | 265246156542201 |
oct | 35220766676437 |
9 | 7111138562013 |
10 | 2012324003103 |
11 | 706470490817 |
12 | 2860032a1793 |
13 | 1179b887c1bb |
14 | 6d57b52c771 |
15 | 37529dee103 |
hex | 1d487db7d1f |
2012324003103 has 128 divisors (see below), whose sum is σ = 3077613895680. Its totient is φ = 1163047818240.
The previous prime is 2012324003099. The next prime is 2012324003161. The reversal of 2012324003103 is 3013004232102.
It is not a de Polignac number, because 2012324003103 - 22 = 2012324003099 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2012324003103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2012324003003) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 2124945676 + ... + 2124946622.
It is an arithmetic number, because the mean of its divisors is an integer number (24043858560).
Almost surely, 22012324003103 is an apocalyptic number.
2012324003103 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
2012324003103 is a deficient number, since it is larger than the sum of its proper divisors (1065289892577).
2012324003103 is a wasteful number, since it uses less digits than its factorization.
2012324003103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1717.
The product of its (nonzero) digits is 864, while the sum is 21.
Adding to 2012324003103 its reverse (3013004232102), we get a palindrome (5025328235205).
The spelling of 2012324003103 in words is "two trillion, twelve billion, three hundred twenty-four million, three thousand, one hundred three".
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