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2012342014225 = 52327192460151
BaseRepresentation
bin11101010010001000111…
…011100101000100010001
321010101012120112010122001
4131102020323211010101
5230432234023423400
64140242425114001
7265246465615564
oct35221073450421
97111176463561
102012342014225
1170647a672844
12286009328901
131179bc51727a
146d57da9a4db
153752b7aaa6a
hex1d488ee5111

2012342014225 has 12 divisors (see below), whose sum is σ = 2495381376640. Its totient is φ = 1609823754000.

The previous prime is 2012342014223. The next prime is 2012342014321. The reversal of 2012342014225 is 5224102432102.

It is not a de Polignac number, because 2012342014225 - 21 = 2012342014223 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2012342014193 and 2012342014202.

It is not an unprimeable number, because it can be changed into a prime (2012342014223) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 412101 + ... + 2048050.

Almost surely, 22012342014225 is an apocalyptic number.

2012342014225 is a gapful number since it is divisible by the number (25) formed by its first and last digit.

It is an amenable number.

2012342014225 is a deficient number, since it is larger than the sum of its proper divisors (483039362415).

2012342014225 is a wasteful number, since it uses less digits than its factorization.

2012342014225 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2492880 (or 2492875 counting only the distinct ones).

The product of its (nonzero) digits is 7680, while the sum is 28.

Adding to 2012342014225 its reverse (5224102432102), we get a palindrome (7236444446327).

The spelling of 2012342014225 in words is "two trillion, twelve billion, three hundred forty-two million, fourteen thousand, two hundred twenty-five".

Divisors: 1 5 25 32719 163595 817975 2460151 12300755 61503775 80493680569 402468402845 2012342014225