Base | Representation |
---|---|
bin | 10010101111011111… |
… | …000011000110001011 |
3 | 1220221110220012020222 |
4 | 102233133003012023 |
5 | 312203222134011 |
6 | 13124515340255 |
7 | 1311456233354 |
oct | 225737030613 |
9 | 56843805228 |
10 | 20124021131 |
11 | 8597537a25 |
12 | 3a975b168b |
13 | 1b892abc16 |
14 | d8c96ad2b |
15 | 7cbab7ddb |
hex | 4af7c318b |
20124021131 has 4 divisors (see below), whose sum is σ = 20667913632. Its totient is φ = 19580128632.
The previous prime is 20124021119. The next prime is 20124021139. The reversal of 20124021131 is 13112042102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20124021131 - 222 = 20119826827 is a prime.
It is a super-2 number, since 2×201240211312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20124021139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 271946195 + ... + 271946268.
It is an arithmetic number, because the mean of its divisors is an integer number (5166978408).
Almost surely, 220124021131 is an apocalyptic number.
20124021131 is a deficient number, since it is larger than the sum of its proper divisors (543892501).
20124021131 is an equidigital number, since it uses as much as digits as its factorization.
20124021131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 543892500.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 20124021131 its reverse (13112042102), we get a palindrome (33236063233).
The spelling of 20124021131 in words is "twenty billion, one hundred twenty-four million, twenty-one thousand, one hundred thirty-one".
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