Base | Representation |
---|---|
bin | 1001001001101011111100… |
… | …10100101000100110000101 |
3 | 2122020211200000201021211020 |
4 | 10210311332110220212011 |
5 | 10114203014011321013 |
6 | 110444505025501353 |
7 | 4144625333112426 |
oct | 444657624504605 |
9 | 78224600637736 |
10 | 20124041120133 |
11 | 6459615641565 |
12 | 23102107a1859 |
13 | b2c8c5789142 |
14 | 4d801a17d64d |
15 | 24d7149d5623 |
hex | 124d7e528985 |
20124041120133 has 32 divisors (see below), whose sum is σ = 28205101808640. Its totient is φ = 12738360159360.
The previous prime is 20124041120129. The next prime is 20124041120147. The reversal of 20124041120133 is 33102114042102.
It is not a de Polignac number, because 20124041120133 - 22 = 20124041120129 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20124041120123) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5506593 + ... + 8400633.
It is an arithmetic number, because the mean of its divisors is an integer number (881409431520).
Almost surely, 220124041120133 is an apocalyptic number.
20124041120133 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
20124041120133 is a deficient number, since it is larger than the sum of its proper divisors (8081060688507).
20124041120133 is a wasteful number, since it uses less digits than its factorization.
20124041120133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2894809.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 20124041120133 its reverse (33102114042102), we get a palindrome (53226155162235).
The spelling of 20124041120133 in words is "twenty trillion, one hundred twenty-four billion, forty-one million, one hundred twenty thousand, one hundred thirty-three".
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