Base | Representation |
---|---|
bin | 1001001001101100000100… |
… | …11011011100000000011001 |
3 | 2122020211211211100101022012 |
4 | 10210312002123130000121 |
5 | 10114203134130344231 |
6 | 110444515530235305 |
7 | 4144630130513561 |
oct | 444660233340031 |
9 | 78224754311265 |
10 | 20124110012441 |
11 | 6459650516356 |
12 | 231022b885b35 |
13 | b2c906b2a716 |
14 | 4d8025393da1 |
15 | 24d71aa92e2b |
hex | 124d826dc019 |
20124110012441 has 4 divisors (see below), whose sum is σ = 20773274851584. Its totient is φ = 19474945173300.
The previous prime is 20124110012411. The next prime is 20124110012483. The reversal of 20124110012441 is 14421001142102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20124110012441 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20124110012411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 324582419525 + ... + 324582419586.
It is an arithmetic number, because the mean of its divisors is an integer number (5193318712896).
Almost surely, 220124110012441 is an apocalyptic number.
It is an amenable number.
20124110012441 is a deficient number, since it is larger than the sum of its proper divisors (649164839143).
20124110012441 is an equidigital number, since it uses as much as digits as its factorization.
20124110012441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 649164839142.
The product of its (nonzero) digits is 512, while the sum is 23.
Adding to 20124110012441 its reverse (14421001142102), we get a palindrome (34545111154543).
The spelling of 20124110012441 in words is "twenty trillion, one hundred twenty-four billion, one hundred ten million, twelve thousand, four hundred forty-one".
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