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2012414504053 is a prime number
BaseRepresentation
bin11101010010001101010…
…000000110110001110101
321010101101121220222222111
4131102031100012301311
5230432411103112203
64140253534531021
7265251336022312
oct35221520066165
97111347828874
102012414504053
11706507584498
12286029666a71
13117a01548165
146d589569d09
1537532d2926d
hex1d48d406c75

2012414504053 has 2 divisors, whose sum is σ = 2012414504054. Its totient is φ = 2012414504052.

The previous prime is 2012414504033. The next prime is 2012414504057. The reversal of 2012414504053 is 3504054142102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1514962182244 + 497452321809 = 1230838^2 + 705303^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2012414504053 is a prime.

It is a super-2 number, since 2×20124145040532 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2012414504057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006207252026 + 1006207252027.

It is an arithmetic number, because the mean of its divisors is an integer number (1006207252027).

Almost surely, 22012414504053 is an apocalyptic number.

It is an amenable number.

2012414504053 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012414504053 is an equidigital number, since it uses as much as digits as its factorization.

2012414504053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 2012414504053 its reverse (3504054142102), we get a palindrome (5516468646155).

The spelling of 2012414504053 in words is "two trillion, twelve billion, four hundred fourteen million, five hundred four thousand, fifty-three".