Base | Representation |
---|---|
bin | 1001001001101100011100… |
… | …11010100100011010101101 |
3 | 2122020212100211202021010121 |
4 | 10210312032122210122231 |
5 | 10114204042121030331 |
6 | 110444551512404541 |
7 | 4144635122026003 |
oct | 444661632443255 |
9 | 78225324667117 |
10 | 20124311111341 |
11 | 6459743a89998 |
12 | 23102870a6751 |
13 | b2c9396aac58 |
14 | 4d8043d80a73 |
15 | 24d72d567c11 |
hex | 124d8e6a46ad |
20124311111341 has 2 divisors, whose sum is σ = 20124311111342. Its totient is φ = 20124311111340.
The previous prime is 20124311111329. The next prime is 20124311111347. The reversal of 20124311111341 is 14311111342102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19772162628100 + 352148483241 = 4446590^2 + 593421^2 .
It is a cyclic number.
It is not a de Polignac number, because 20124311111341 - 221 = 20124309014189 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20124311111347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10062155555670 + 10062155555671.
It is an arithmetic number, because the mean of its divisors is an integer number (10062155555671).
Almost surely, 220124311111341 is an apocalyptic number.
It is an amenable number.
20124311111341 is a deficient number, since it is larger than the sum of its proper divisors (1).
20124311111341 is an equidigital number, since it uses as much as digits as its factorization.
20124311111341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 20124311111341 its reverse (14311111342102), we get a palindrome (34435422453443).
The spelling of 20124311111341 in words is "twenty trillion, one hundred twenty-four billion, three hundred eleven million, one hundred eleven thousand, three hundred forty-one".
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