Base | Representation |
---|---|
bin | 101101110000011110010001… |
… | …100100111001111111001111 |
3 | 222101112122201002111111000012 |
4 | 231300132101210321333033 |
5 | 202334131420031300403 |
6 | 1552001453035223435 |
7 | 60250223326554323 |
oct | 5560362144717717 |
9 | 871478632444005 |
10 | 201243135025103 |
11 | 59138809362216 |
12 | 1a6a23268a7b7b |
13 | 883a1b9298482 |
14 | 379a310c2d983 |
15 | 183ebe0ac7ed8 |
hex | b70791939fcf |
201243135025103 has 2 divisors, whose sum is σ = 201243135025104. Its totient is φ = 201243135025102.
The previous prime is 201243135025063. The next prime is 201243135025133. The reversal of 201243135025103 is 301520531342102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201243135025103 - 26 = 201243135025039 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 201243135025103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201243135025133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100621567512551 + 100621567512552.
It is an arithmetic number, because the mean of its divisors is an integer number (100621567512552).
Almost surely, 2201243135025103 is an apocalyptic number.
201243135025103 is a deficient number, since it is larger than the sum of its proper divisors (1).
201243135025103 is an equidigital number, since it uses as much as digits as its factorization.
201243135025103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 201243135025103 its reverse (301520531342102), we get a palindrome (502763666367205).
The spelling of 201243135025103 in words is "two hundred one trillion, two hundred forty-three billion, one hundred thirty-five million, twenty-five thousand, one hundred three".
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