Base | Representation |
---|---|
bin | 1001001001101100101100… |
… | …01111000110011000100111 |
3 | 2122020212200222122110222002 |
4 | 10210312112033012120213 |
5 | 10114204324213304341 |
6 | 110445012520555515 |
7 | 4144641304222514 |
oct | 444662617063047 |
9 | 78225628573862 |
10 | 20124442322471 |
11 | 6459801058843 |
12 | 2310303022b9b |
13 | b2c95a92ba86 |
14 | 4d805757830b |
15 | 24d739d3529b |
hex | 124d963c6627 |
20124442322471 has 2 divisors, whose sum is σ = 20124442322472. Its totient is φ = 20124442322470.
The previous prime is 20124442322431. The next prime is 20124442322477. The reversal of 20124442322471 is 17422324442102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20124442322471 is a prime.
It is a super-3 number, since 3×201244423224713 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20124442322477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10062221161235 + 10062221161236.
It is an arithmetic number, because the mean of its divisors is an integer number (10062221161236).
Almost surely, 220124442322471 is an apocalyptic number.
20124442322471 is a deficient number, since it is larger than the sum of its proper divisors (1).
20124442322471 is an equidigital number, since it uses as much as digits as its factorization.
20124442322471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172032, while the sum is 38.
Adding to 20124442322471 its reverse (17422324442102), we get a palindrome (37546766764573).
The spelling of 20124442322471 in words is "twenty trillion, one hundred twenty-four billion, four hundred forty-two million, three hundred twenty-two thousand, four hundred seventy-one".
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