Base | Representation |
---|---|
bin | 11101010010001111000… |
… | …001100011000010101101 |
3 | 21010101110200212211220101 |
4 | 131102033001203002231 |
5 | 230432441211221333 |
6 | 4140300520151101 |
7 | 265252146550165 |
oct | 35221701430255 |
9 | 7111420784811 |
10 | 2012444242093 |
11 | 70652234608a |
12 | 286037608491 |
13 | 117a0775ab2c |
14 | 6d58d4ab5a5 |
15 | 3753575067d |
hex | 1d48f0630ad |
2012444242093 has 2 divisors, whose sum is σ = 2012444242094. Its totient is φ = 2012444242092.
The previous prime is 2012444242051. The next prime is 2012444242201. The reversal of 2012444242093 is 3902424442102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1501931134089 + 510513108004 = 1225533^2 + 714502^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012444242093 - 217 = 2012444111021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2012444242493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006222121046 + 1006222121047.
It is an arithmetic number, because the mean of its divisors is an integer number (1006222121047).
Almost surely, 22012444242093 is an apocalyptic number.
It is an amenable number.
2012444242093 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012444242093 is an equidigital number, since it uses as much as digits as its factorization.
2012444242093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110592, while the sum is 37.
Adding to 2012444242093 its reverse (3902424442102), we get a palindrome (5914868684195).
The spelling of 2012444242093 in words is "two trillion, twelve billion, four hundred forty-four million, two hundred forty-two thousand, ninety-three".
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