Base | Representation |
---|---|
bin | 1001001001101110001000… |
… | …01011111110000111110011 |
3 | 2122020221200201021212101112 |
4 | 10210313010023332013303 |
5 | 10114212414043113011 |
6 | 110445221220423535 |
7 | 4144666355100626 |
oct | 444670413760763 |
9 | 78227621255345 |
10 | 20125213254131 |
11 | 645a067245147 |
12 | 2310499247bab |
13 | b2ca51574a5b |
14 | 4d80cbad7dbd |
15 | 24d78286958b |
hex | 124dc42fe1f3 |
20125213254131 has 2 divisors, whose sum is σ = 20125213254132. Its totient is φ = 20125213254130.
The previous prime is 20125213254127. The next prime is 20125213254163. The reversal of 20125213254131 is 13145231252102.
It is an a-pointer prime, because the next prime (20125213254163) can be obtained adding 20125213254131 to its sum of digits (32).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20125213254131 - 22 = 20125213254127 is a prime.
It is a super-2 number, since 2×201252132541312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20125213254931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10062606627065 + 10062606627066.
It is an arithmetic number, because the mean of its divisors is an integer number (10062606627066).
Almost surely, 220125213254131 is an apocalyptic number.
20125213254131 is a deficient number, since it is larger than the sum of its proper divisors (1).
20125213254131 is an equidigital number, since it uses as much as digits as its factorization.
20125213254131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 32.
The spelling of 20125213254131 in words is "twenty trillion, one hundred twenty-five billion, two hundred thirteen million, two hundred fifty-four thousand, one hundred thirty-one".
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