Base | Representation |
---|---|
bin | 1001001001110000000101… |
… | …01101100100101010000101 |
3 | 2122021001101211011101100201 |
4 | 10210320002231210222011 |
5 | 10114222041114000432 |
6 | 110445513252210501 |
7 | 4145034353315152 |
oct | 444700255445205 |
9 | 78231354141321 |
10 | 20126262250117 |
11 | 645a555393381 |
12 | 2310730609a31 |
13 | b2cb8a9a833a |
14 | 4d818b15b229 |
15 | 24d7e49c7ee7 |
hex | 124e02b64a85 |
20126262250117 has 2 divisors, whose sum is σ = 20126262250118. Its totient is φ = 20126262250116.
The previous prime is 20126262250067. The next prime is 20126262250121. The reversal of 20126262250117 is 71105226262102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17988040395361 + 2138221854756 = 4241231^2 + 1462266^2 .
It is a cyclic number.
It is not a de Polignac number, because 20126262250117 - 215 = 20126262217349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20126262250177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10063131125058 + 10063131125059.
It is an arithmetic number, because the mean of its divisors is an integer number (10063131125059).
Almost surely, 220126262250117 is an apocalyptic number.
It is an amenable number.
20126262250117 is a deficient number, since it is larger than the sum of its proper divisors (1).
20126262250117 is an equidigital number, since it uses as much as digits as its factorization.
20126262250117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 37.
The spelling of 20126262250117 in words is "twenty trillion, one hundred twenty-six billion, two hundred sixty-two million, two hundred fifty thousand, one hundred seventeen".
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