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20126271663557 is a prime number
BaseRepresentation
bin1001001001110000000110…
…10001011110110111000101
32122021001102110212122011122
410210320003101132313011
510114222101021213212
6110445514230043325
74145034526322453
oct444700321366705
978231373778148
1020126271663557
11645a55a732884
1223107337a9545
13b2cb8c922c17
144d818c4cb9d3
1524d7e5737272
hex124e0345edc5

20126271663557 has 2 divisors, whose sum is σ = 20126271663558. Its totient is φ = 20126271663556.

The previous prime is 20126271663481. The next prime is 20126271663587. The reversal of 20126271663557 is 75536617262102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19868289952996 + 257981710561 = 4457386^2 + 507919^2 .

It is a cyclic number.

It is not a de Polignac number, because 20126271663557 - 28 = 20126271663301 is a prime.

It is a super-2 number, since 2×201262716635572 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20126271663499 and 20126271663508.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20126271663587) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10063135831778 + 10063135831779.

It is an arithmetic number, because the mean of its divisors is an integer number (10063135831779).

Almost surely, 220126271663557 is an apocalyptic number.

It is an amenable number.

20126271663557 is a deficient number, since it is larger than the sum of its proper divisors (1).

20126271663557 is an equidigital number, since it uses as much as digits as its factorization.

20126271663557 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6350400, while the sum is 53.

The spelling of 20126271663557 in words is "twenty trillion, one hundred twenty-six billion, two hundred seventy-one million, six hundred sixty-three thousand, five hundred fifty-seven".