Base | Representation |
---|---|
bin | 1001001001110000001101… |
… | …10001100101111001111111 |
3 | 2122021001120120102101210202 |
4 | 10210320012301211321333 |
5 | 10114222211041201141 |
6 | 110445524125154115 |
7 | 4145036141556620 |
oct | 444700661457177 |
9 | 78231516371722 |
10 | 20126330412671 |
11 | 645a58a90996a |
12 | 231074b3bb93b |
13 | b2cb9bb52702 |
14 | 4d8196221a47 |
15 | 24d7ea98e49b |
hex | 124e06c65e7f |
20126330412671 has 4 divisors (see below), whose sum is σ = 23001520471632. Its totient is φ = 17251140353712.
The previous prime is 20126330412653. The next prime is 20126330412719. The reversal of 20126330412671 is 17621403362102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20126330412671 - 218 = 20126330150527 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20126330412641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1437595029470 + ... + 1437595029483.
It is an arithmetic number, because the mean of its divisors is an integer number (5750380117908).
Almost surely, 220126330412671 is an apocalyptic number.
20126330412671 is a deficient number, since it is larger than the sum of its proper divisors (2875190058961).
20126330412671 is an equidigital number, since it uses as much as digits as its factorization.
20126330412671 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2875190058960.
The product of its (nonzero) digits is 72576, while the sum is 38.
Adding to 20126330412671 its reverse (17621403362102), we get a palindrome (37747733774773).
The spelling of 20126330412671 in words is "twenty trillion, one hundred twenty-six billion, three hundred thirty million, four hundred twelve thousand, six hundred seventy-one".
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