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201300020001347 is a prime number
BaseRepresentation
bin101101110001010011010000…
…001011110111101001000011
3222101202002112111121200111012
4231301103100023313221003
5202341044420110020342
61552043541425511135
760254306103102161
oct5561232013675103
9871662474550435
10201300020001347
115915a94a456883
121a6b13614a24ab
13884268356a227
14379cd89ad8231
15184141eb15b82
hexb714d02f7a43

201300020001347 has 2 divisors, whose sum is σ = 201300020001348. Its totient is φ = 201300020001346.

The previous prime is 201300020001313. The next prime is 201300020001373. The reversal of 201300020001347 is 743100020003102.

201300020001347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201300020001347 is a prime.

It is not a weakly prime, because it can be changed into another prime (201300020001947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100650010000673 + 100650010000674.

It is an arithmetic number, because the mean of its divisors is an integer number (100650010000674).

Almost surely, 2201300020001347 is an apocalyptic number.

201300020001347 is a deficient number, since it is larger than the sum of its proper divisors (1).

201300020001347 is an equidigital number, since it uses as much as digits as its factorization.

201300020001347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 23.

Adding to 201300020001347 its reverse (743100020003102), we get a palindrome (944400040004449).

The spelling of 201300020001347 in words is "two hundred one trillion, three hundred billion, twenty million, one thousand, three hundred forty-seven".