Base | Representation |
---|---|
bin | 1011101101111001101… |
… | …0101000111111011011 |
3 | 201020120221111121100011 |
4 | 2323132122220333123 |
5 | 11244230301134321 |
6 | 232250450022351 |
7 | 20354254643212 |
oct | 2733632507733 |
9 | 636527447304 |
10 | 201300021211 |
11 | 784096833a3 |
12 | 3301ab779b7 |
13 | 15ca07639b3 |
14 | 9a58a0a079 |
15 | 538266aae1 |
hex | 2ede6a8fdb |
201300021211 has 2 divisors, whose sum is σ = 201300021212. Its totient is φ = 201300021210.
The previous prime is 201300021203. The next prime is 201300021269. The reversal of 201300021211 is 112120003102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201300021211 - 23 = 201300021203 is a prime.
It is a super-4 number, since 4×2013000212114 (a number of 46 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 201300021191 and 201300021200.
It is not a weakly prime, because it can be changed into another prime (201300021281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100650010605 + 100650010606.
It is an arithmetic number, because the mean of its divisors is an integer number (100650010606).
Almost surely, 2201300021211 is an apocalyptic number.
201300021211 is a deficient number, since it is larger than the sum of its proper divisors (1).
201300021211 is an equidigital number, since it uses as much as digits as its factorization.
201300021211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 201300021211 its reverse (112120003102), we get a palindrome (313420024313).
The spelling of 201300021211 in words is "two hundred one billion, three hundred million, twenty-one thousand, two hundred eleven".
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