Base | Representation |
---|---|
bin | 1011101101111001101… |
… | …1101110000111011001 |
3 | 201020120222000222201121 |
4 | 2323132123232013121 |
5 | 11244230334214340 |
6 | 232250500045241 |
7 | 20354260232530 |
oct | 2733633560731 |
9 | 636528028647 |
10 | 201300304345 |
11 | 78409857098 |
12 | 3301b093821 |
13 | 15ca083282a |
14 | 9a58a81317 |
15 | 53826c494a |
hex | 2ede6ee1d9 |
201300304345 has 64 divisors (see below), whose sum is σ = 287779184640. Its totient is φ = 132256051200.
The previous prime is 201300304333. The next prime is 201300304349. The reversal of 201300304345 is 543403003102.
It is not a de Polignac number, because 201300304345 - 215 = 201300271577 is a prime.
It is not an unprimeable number, because it can be changed into a prime (201300304349) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 101002669 + ... + 101004661.
It is an arithmetic number, because the mean of its divisors is an integer number (4496549760).
Almost surely, 2201300304345 is an apocalyptic number.
It is an amenable number.
201300304345 is a deficient number, since it is larger than the sum of its proper divisors (86478880295).
201300304345 is a wasteful number, since it uses less digits than its factorization.
201300304345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2746.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 201300304345 its reverse (543403003102), we get a palindrome (744703307447).
The spelling of 201300304345 in words is "two hundred one billion, three hundred million, three hundred four thousand, three hundred forty-five".
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