Base | Representation |
---|---|
bin | 10010101111110101… |
… | …111111010111010001 |
3 | 1220221220012201221112 |
4 | 102233311333113101 |
5 | 312211242111103 |
6 | 13125252303105 |
7 | 1311561322064 |
oct | 225765772721 |
9 | 56856181845 |
10 | 20130035153 |
11 | 859a975398 |
12 | 3a99611a95 |
13 | 1b8a606407 |
14 | d8d6948db |
15 | 7cc3a4cd8 |
hex | 4afd7f5d1 |
20130035153 has 2 divisors, whose sum is σ = 20130035154. Its totient is φ = 20130035152.
The previous prime is 20130035113. The next prime is 20130035209. The reversal of 20130035153 is 35153003102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 17712149569 + 2417885584 = 133087^2 + 49172^2 .
It is a cyclic number.
It is not a de Polignac number, because 20130035153 - 210 = 20130034129 is a prime.
It is a super-2 number, since 2×201300351532 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20130035113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065017576 + 10065017577.
It is an arithmetic number, because the mean of its divisors is an integer number (10065017577).
Almost surely, 220130035153 is an apocalyptic number.
It is an amenable number.
20130035153 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130035153 is an equidigital number, since it uses as much as digits as its factorization.
20130035153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1350, while the sum is 23.
Adding to 20130035153 its reverse (35153003102), we get a palindrome (55283038255).
The spelling of 20130035153 in words is "twenty billion, one hundred thirty million, thirty-five thousand, one hundred fifty-three".
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