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20130035153 is a prime number
BaseRepresentation
bin10010101111110101…
…111111010111010001
31220221220012201221112
4102233311333113101
5312211242111103
613125252303105
71311561322064
oct225765772721
956856181845
1020130035153
11859a975398
123a99611a95
131b8a606407
14d8d6948db
157cc3a4cd8
hex4afd7f5d1

20130035153 has 2 divisors, whose sum is σ = 20130035154. Its totient is φ = 20130035152.

The previous prime is 20130035113. The next prime is 20130035209. The reversal of 20130035153 is 35153003102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17712149569 + 2417885584 = 133087^2 + 49172^2 .

It is a cyclic number.

It is not a de Polignac number, because 20130035153 - 210 = 20130034129 is a prime.

It is a super-2 number, since 2×201300351532 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20130035113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065017576 + 10065017577.

It is an arithmetic number, because the mean of its divisors is an integer number (10065017577).

Almost surely, 220130035153 is an apocalyptic number.

It is an amenable number.

20130035153 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130035153 is an equidigital number, since it uses as much as digits as its factorization.

20130035153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1350, while the sum is 23.

Adding to 20130035153 its reverse (35153003102), we get a palindrome (55283038255).

The spelling of 20130035153 in words is "twenty billion, one hundred thirty million, thirty-five thousand, one hundred fifty-three".