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201301114133 = 728757302019
BaseRepresentation
bin1011101101111001111…
…0110011110100010101
3201020121000120010112202
42323132132303310111
511244231041123013
6232250525254245
720354300144450
oct2733636636425
9636530503482
10201301114133
117840a25a539
123301b404385
1315ca0a572b2
149a58c12497
1553827d4858
hex2ede7b3d15

201301114133 has 4 divisors (see below), whose sum is σ = 230058416160. Its totient is φ = 172543812108.

The previous prime is 201301114129. The next prime is 201301114159. The reversal of 201301114133 is 331411103102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 201301114133 - 22 = 201301114129 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201301114033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14378651003 + ... + 14378651016.

It is an arithmetic number, because the mean of its divisors is an integer number (57514604040).

Almost surely, 2201301114133 is an apocalyptic number.

It is an amenable number.

201301114133 is a deficient number, since it is larger than the sum of its proper divisors (28757302027).

201301114133 is an equidigital number, since it uses as much as digits as its factorization.

201301114133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28757302026.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 201301114133 its reverse (331411103102), we get a palindrome (532712217235).

The spelling of 201301114133 in words is "two hundred one billion, three hundred one million, one hundred fourteen thousand, one hundred thirty-three".

Divisors: 1 7 28757302019 201301114133