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2013011212309 is a prime number
BaseRepresentation
bin11101010010110000110…
…100010111100000010101
321010102221012201220211021
4131102300310113200111
5230440121332243214
64140433052241141
7265302202661446
oct35226064274025
97112835656737
102013011212309
11706793394209
122861754701b1
13117a98060676
146d6048d72cd
153756a3e6924
hex1d4b0d17815

2013011212309 has 2 divisors, whose sum is σ = 2013011212310. Its totient is φ = 2013011212308.

The previous prime is 2013011212297. The next prime is 2013011212339. The reversal of 2013011212309 is 9032121103102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1494071071684 + 518940140625 = 1222322^2 + 720375^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013011212309 - 239 = 1463255398421 is a prime.

It is a super-2 number, since 2×20130112123092 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013011212339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006505606154 + 1006505606155.

It is an arithmetic number, because the mean of its divisors is an integer number (1006505606155).

Almost surely, 22013011212309 is an apocalyptic number.

It is an amenable number.

2013011212309 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013011212309 is an equidigital number, since it uses as much as digits as its factorization.

2013011212309 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 2013011212309 in words is "two trillion, thirteen billion, eleven million, two hundred twelve thousand, three hundred nine".